Question:
If log2X + log4X = log0.25
and x > 0, then x is
If log2X + log4X = log0.25
A. 6-1/6
B. 61/6
C. 3-1/3
D. 61/3
Correct Answer: (A)
Explanation:
log2x + log4x = log0.25
log2x +
= log0.25
log2x *
= log0.25
log2x * 3 = 2log0.25
log2x3 = log0.256
log2x3 = -log46
log2x3 = 
log2x3 = 
2log2x3 = -log26
2log2x3 + log26
= 0
log26x6 = 0
6x6 = 1
x6 = 
x =
Choice (A).
Level of difficulty 2
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