# Number Theory Questions - Factors

Questions:
1. How many numbers are there less than 100 that cannot be written as a multiple of a perfect square greater than 1?
2. Find the smallest number that has exactly 18 factors?

Qn 1: 61 numbers
Qn 2: 180

Qn1 :How many numbers are there less than 100 that cannot be written as a multiple of a perfect square?

To begin with, all prime numbers will be part of this list. There are 25 primes less than 100. (That is a nugget that can come in handy)

Apart from this, any number that can be written as a product of two or more primes will be there on this list. That is, any number of the form pq, or pqr, or pqrs will be there on this list (where p, q, r, s are primes). A number of the form pnq cannot be a part of this list if n is greater than 1, as then the number will be a multiple of p2.

This is a brute-force question.

First let us think of all multiples of 2 * prime number. This includes 2*3, 2*5, 2*7, 2 * 11 all the way up to 2*47 (14 numbers)

The, we move on to all numbers of the type 3 * prime number 3*5, 3*7 all the way up to 3*31 (9 numbers)

Then, all numbers of the type 5 * prime number – 5*7, 5*11, 5*13, 5*17, 5*19 (5 numbers),

Then, all numbers of the type 7 * prime number  and then 7*11, 7*13 (2 numbers).

There are no numbers of the form 11 * prime number which have not been counted earlier.

Post this, we need to count all numbers of the form p*q*r, where p, q, r are all prime.
In this list, we have 2*3*5, 2*3*7, 2*3*11, 2*3*13 and 2*5*7. Adding 1 to this list, we get totally 36 different composite numbers.

Along with the 25 prime numbers, we get 61 numbers that cannot be written as a product of a perfect square greater than 1

Alternative Method

There is another method of solving this question.

We can list all multiples of perfect squares (without repeating any number) and subtract this from 99

4 - there are 24 multiples of 4 { 4, 8, 12, …96}
9 - There are 11 multiples, 2 are common with 4 (36 and 72), so let us add 9 new numbers to the list{ 9, 18, 27, ….99}
16 - 0 new multiples
25 - 3 new multiples { 25, 50, 75
36 – 0 new ones
49 – 2 { 49, 98}
64 - 0
81 - 0

So, total multiples of perfect squares are 38. There are 99 numbers totally. So, there are 61 numbers that are not multiples of perfect squares

This is a difficult and time-consuming question. But a question that once solved, helps practice brute-force counting. Another takeaway is the fact that there are 25 primes less than 100. There is a function called pi(x) that gives the number of primes less than or equal to x. pi(10) = 4, pi(100) = 25

4. Find the smallest number that has exactly 18 factors?

Any number of the form paqbrc will have (a+1) (b+1)(c+1) factors, where p, q, r are prime. (This is a very important idea)
Now, the number we are looking for has 18 factors. It can comprise one prime, two primes or three primes.
Now, 18 can be written as 1 * 18 or 3 * 6 or 9 * 2 or 2 * 3 * 3

If we take the underlying prime factorization of N to be paqb, then it can be of the form
p1q8 or p2 q5

If we take the underlying prime factorization of N to be pa, then it can be of the form
p17
If we take the underlying prime factorization of N to be paqbrc, then it can be of the form
p1q1r2
So, N can be of the form p17, p2q5, p1q8 or p1q2r2

Importantly, these are the only possible prime factorizations that can result in a number having 18 factors.

Now, let us think of the smallest possible number in each scenario
p17 - Smallest number = 217
p2q5 – 32 * 25
p1q8 – 31 * 28
p1q1r2 – 51 * 31 * 22
The smallest of these numbers is 51 * 31 * 22  = 180

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IIM CAT Preparation Tips: Number Theory Questions - Factors

## Oct 28, 2010

### Number Theory Questions - Factors

Questions:
1. How many numbers are there less than 100 that cannot be written as a multiple of a perfect square greater than 1?
2. Find the smallest number that has exactly 18 factors?

Qn 1: 61 numbers
Qn 2: 180

Qn1 :How many numbers are there less than 100 that cannot be written as a multiple of a perfect square?

To begin with, all prime numbers will be part of this list. There are 25 primes less than 100. (That is a nugget that can come in handy)

Apart from this, any number that can be written as a product of two or more primes will be there on this list. That is, any number of the form pq, or pqr, or pqrs will be there on this list (where p, q, r, s are primes). A number of the form pnq cannot be a part of this list if n is greater than 1, as then the number will be a multiple of p2.

This is a brute-force question.

First let us think of all multiples of 2 * prime number. This includes 2*3, 2*5, 2*7, 2 * 11 all the way up to 2*47 (14 numbers)

The, we move on to all numbers of the type 3 * prime number 3*5, 3*7 all the way up to 3*31 (9 numbers)

Then, all numbers of the type 5 * prime number – 5*7, 5*11, 5*13, 5*17, 5*19 (5 numbers),

Then, all numbers of the type 7 * prime number  and then 7*11, 7*13 (2 numbers).

There are no numbers of the form 11 * prime number which have not been counted earlier.

Post this, we need to count all numbers of the form p*q*r, where p, q, r are all prime.
In this list, we have 2*3*5, 2*3*7, 2*3*11, 2*3*13 and 2*5*7. Adding 1 to this list, we get totally 36 different composite numbers.

Along with the 25 prime numbers, we get 61 numbers that cannot be written as a product of a perfect square greater than 1

Alternative Method

There is another method of solving this question.

We can list all multiples of perfect squares (without repeating any number) and subtract this from 99

4 - there are 24 multiples of 4 { 4, 8, 12, …96}
9 - There are 11 multiples, 2 are common with 4 (36 and 72), so let us add 9 new numbers to the list{ 9, 18, 27, ….99}
16 - 0 new multiples
25 - 3 new multiples { 25, 50, 75
36 – 0 new ones
49 – 2 { 49, 98}
64 - 0
81 - 0

So, total multiples of perfect squares are 38. There are 99 numbers totally. So, there are 61 numbers that are not multiples of perfect squares

This is a difficult and time-consuming question. But a question that once solved, helps practice brute-force counting. Another takeaway is the fact that there are 25 primes less than 100. There is a function called pi(x) that gives the number of primes less than or equal to x. pi(10) = 4, pi(100) = 25

4. Find the smallest number that has exactly 18 factors?

Any number of the form paqbrc will have (a+1) (b+1)(c+1) factors, where p, q, r are prime. (This is a very important idea)
Now, the number we are looking for has 18 factors. It can comprise one prime, two primes or three primes.
Now, 18 can be written as 1 * 18 or 3 * 6 or 9 * 2 or 2 * 3 * 3

If we take the underlying prime factorization of N to be paqb, then it can be of the form
p1q8 or p2 q5

If we take the underlying prime factorization of N to be pa, then it can be of the form
p17
If we take the underlying prime factorization of N to be paqbrc, then it can be of the form
p1q1r2
So, N can be of the form p17, p2q5, p1q8 or p1q2r2

Importantly, these are the only possible prime factorizations that can result in a number having 18 factors.

Now, let us think of the smallest possible number in each scenario
p17 - Smallest number = 217
p2q5 – 32 * 25
p1q8 – 31 * 28
p1q1r2 – 51 * 31 * 22
The smallest of these numbers is 51 * 31 * 22  = 180

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