Question:
3sinx
+ 4cosx + r is always greater than or equal to 0. What is the smallest value
‘r’ can to take?
A. 5
B. -5
C. 4
D. 3
Correct
Answer: (A)
Explanation:
3sinx + 4cosx ≥ -r
≥ -r
= cosA
=> sinA =
5(sinx cosA + sinA cosA) ≥ -r
5(sin(x + A) ≥ -r
5sin (x + A) ≥ -r
-1 < sin (angle) <
1
5sin (x + A) ≥ -5
rmin = 5
Difficulty Level 2