### CAT - Logarithms

**Question:**

If log

_{2}X + log

_{4}X = log

_{0.25}and x > 0, then x is

A. 6

^{-1/6}
B. 6

^{1/6}
C. 3

^{-1/3}
D. 6

^{1/3}**Correct Answer: (A)**

**Explanation:**

log

_{2}x + log_{4}x = log_{0.25}
log

_{2}x + = log_{0.25}
log

_{2}x * = log_{0.25}
log

_{2}x * 3 = 2log_{0.25}
log

_{2}x^{3}= log_{0.25}6
log

_{2}x^{3}= -log_{4}6
log

_{2}x^{3}=
log

_{2}x^{3}=
2log

_{2}x^{3}= -log_{2}6
2log

_{2}x^{3}+ log_{2}6 = 0
log

_{2}6x^{6}= 0
6x

^{6}= 1
x

^{6}=
x = Choice (A).

**Level of difficulty 2**

Labels: 2IIM, 2iim Chennai, CAT 2013, CAT 2013 questions, CAT 2013 Solutions, CAT Coaching classes Chennai, CAT Logarithms

## 3 Comments:

good one

Yup really

Yup good one

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